general chemistry chapter 6 chang 4

3)Calculate ∆H(rxn)for the reaction:

5N2O4(l) +4N2H3CH3(l) = 12H2O(g) + 9N2(g) + 4CO2(g)

Given:

N2H3CH3(l)     ∆H(rxn) = 54 kJ/mole

N2O4(l)            âˆ†H(rxn) = -20kJ/mole

 

Do you need a similar assignment done for you from scratch? We have qualified writers to help you. We assure you an A+ quality paper that is free from plagiarism. Order now for an Amazing Discount!
Use Discount Code “Newclient” for a 15% Discount!

NB: We do not resell papers. Upon ordering, we do an original paper exclusively for you.


The post general chemistry chapter 6 chang 4 appeared first on Nursing Writers Hub.

"Is this qustion part of your assignmentt? We will write the assignment for you. click order now and get up to 40% Discount"