general chemistry chapter 6 chang 4

3)Calculate ∆H(rxn)for the reaction:

5N2O4(l) +4N2H3CH3(l) = 12H2O(g) + 9N2(g) + 4CO2(g)


N2H3CH3(l)     ∆H(rxn) = 54 kJ/mole

N2O4(l)            âˆ†H(rxn) = -20kJ/mole


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